How can I find all matches to a regular expression in Python?
Harness the power of re.findall()
to retrieve all occurrences of a regex pattern in a string, in a distilled and streamlined fashion:
For instance, if we want words that kick off with an 'S':
The output we get is: ['Spain']
. A no-nonsense, effective approach.
Using finditer for better performance
When wrestling with substantial text bodies or requiring more match details, re.finditer()
stands as an efficient alternative. It returns an iterator yielding MatchObject
instances instead of a list:
Squeezing information from MatchObjects
Each MatchObject
from re.finditer()
is a goldmine of details about each match. You can extract these nuggets of information through methods such as .group()
, .start()
, .end()
, and .groups()
. Behold the power of .group()
:
Findall and capturing groups
If your regular expression incorporates groups, re.findall()
brings home just the groups. Given several groups, you receive a list of tuples:
This yields group party pairs: [('The', 'Spain'), ('The', 'stays')]
.
Beware of regex's greedy nature
Regex can get a bit too eager sometimes. Domesticate its greedy nature with a non-greedy match ?
to avoid any surprising findings:
Flags: the secret spices of regex
Meetings with flags like re.IGNORECASE
can bring a radical change of attitude. Think of them as secret spices for flavorful results:
Dealing with the Unicode dragon
Taming the dragon of Unicode matching is no child's play. Equip yourself with the flag re.UNICODE
to secure your regex from any Unicode character inconsistencies:
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