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Java.net.malformedurlexception: no protocol

java
xml-parsing
memory-management
streaming-data
Nikita BarsukovbyNikita Barsukov·Aug 22, 2024
TLDR

The MalformedURLException arises when there's no protocol in the URL. This can be corrected by appending http:// or https:// to your URL string:

URL url = new URL("http://example.com"); // Don't forget 'http://' or 'https://'

For string inputs with XML data, using StringReader wrapped inside an InputSource resolves the problem while parsing using DocumentBuilder:

DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder(); // Unleashing the builder! InputSource source = new InputSource(new StringReader(xmlString)); // StringReader to the rescue! Document document = builder.parse(source); // Onwards to parsing!

File objects or InputStream instances can be used for an optimized parsing process, steering clear of conversion overhead and string protocol issues.

Effective techniques for XML parsing

Overcoming large files

To deal with large-sized files, prefer to use InputStream as it helps in avoiding the scenario of loading the entire content into memory:

InputStream inputStream = new FileInputStream("path/to/file.xml"); // Personal stream king (PSK) for XML Document document = builder.parse(inputStream); // Parse like a boss

This guards against system overload and efficiently manages large XML content.

Using File objects for maximum efficiency

Using File objects can optimize the parsing process giving direct access to the XML content:

File xmlFile = new File("path/to/file.xml"); // Bringing XML to file... Speed Racer Go! Document document = builder.parse(xmlFile); // "I got the power!" - builder

Parsing XML from strings

Suppose you have XML as strings. Use the StringReader like so:

String xmlString = "<root>...</root>"; // "I am Groot."- XML string Document document = builder.parse(new InputSource(new StringReader(xmlString))); // Star Parser handles Groot

Just passing a string to DocumentBuilder.parse() might result in MalformedURLException.

Verifying XML format

Ensure the XML is well-structured. If not, you could end up facing errors:

boolean isValidXML = XMLValidator.validate(xmlString); // "To be XML or not to be XML, that is the question." if (isValidXML) { Document document = builder.parse(new InputSource(new StringReader(xmlString))); }

Following these steps makes your ride with XML parsing smoother and mishap-free!

Tackling large XML data

Stream it to manage content

When dealing with larger data sets, the use of streams can be a lifesaver:

try (InputStream bigXMLStream = new FileInputStream("large.xml")) { // Netflix for XML, streaming the large one! Document document = builder.parse(bigXMLStream); // Parsing, now in HD! }

This practice prevents memory issues, improving the scalability of your application.

Parsing XML in Resource-limited environments

If resources are sparse, move to the SAX parser. It allows niche event-based XML parsing:

SAXParserFactory factory = SAXParserFactory.newInstance(); SAXParser saxParser = factory.newSAXParser(); saxParser.parse(new InputSource(new StringReader(xmlString)), handler); // SAX and the XML, a compact tale!

This technique reads XML without gobbling up all the memory, making your code resource-conscious.