How to get the caller's method name in the called method?
Here's how to acquire the caller's method name with the help of the inspect.currentframe()
function:
The output? Caller: caller
. Saucy, isn't it? We fetched the calling method name with just a few lines. Quite the pythonic way.
Substitutes and Stumbling Blocks
If inspect
doesn't get you there, you might be tempted by sys._getframe()
. But not so fast, my eager friend:
The output remains the same but, beware: sys._getframe()
is internal and unofficial. Using it in production code is like asking for a Joker in your Python's Gotham City.
The Hustle for Efficiency
Now remember, inspect.stack()
might eat pie right from your performance resources:
Less resource-hogging, and faster than a caffeinated python, this variant gets you there quicker:
If you're on a debugging safari, inspect.stack()
is your telescope, but for production, jump on the speed train with currentframe()
.
Memory Quirks: the Frame Leaks
Here's a quirk: holding onto the entire frame object longer than necessary can cause frame leaks. Handle with care, disarming the ora after extracting the information.
Your Call Stack Guide
Let's dive into how the call stack can serve you:
This copious procedure can scout the caller's context more effectively than simple method name retrieval.
Contingencies: Different Contexts
Classes and Modules
When dealing with class methods or different modules, the game takes a twist:
This confirms that method_one
is calling method_two
.
The Case of the Nameless
Our detective turns to the nameless suspects - lambdas and the like:
There are no escapees under the watch of inspect.stack()[1][3]
, which returns '<lambda>'
.
Main Scope Calls
Sometimes, a called method might need to check if it's been called from the main scope:
This snippet conclusively reveals if the method was directly invoked from the main module.
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