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How to remove specific elements in a numpy array

python
numpy
array
dataframe
Alex KataevbyAlex Kataev·Feb 20, 2025
TLDR

In need to remove elements from a numpy array in a jiffy? Here's the trick, use boolean indexing:

import numpy as np arr = np.array([1, 2, 3, 4, 5]) # This is your array remove = [2, 4] # The culprits you want removed # Apply the mask to retain only the innocents filtered_arr = arr[~np.isin(arr, remove)] print(filtered_arr) # [1, 3, 5]

Voila! You've mastered wielding the powerful combo of np.isin with bitwise negation ~ to shoo away unwanted elements.

Python meets immutability

In Numpy, arrays are immutable, meaning alterations spawn new arrays, like a cellular automaton. So perform operations wisely to save memory and uphold execution performance.

Index-based removal: np.delete to the rescue

To remove elements by index, use np.delete(). It's your loyal servant:

arr = np.array([1, 2, 3, 4, 5]) indices_to_remove = [1, 3] # Indices of the unchosen ones # Excommunicate elements at indices 1 and 3 new_arr = np.delete(arr, indices_to_remove) print(new_arr) # [1, 3, 5]

But remember, np.delete shows respect to the original array, and provides you with a fresh array.

The art of exclusion: employing set operations

np.setdiff1d() is the Picasso of subtracting numpy sets, it easily sketches out the elements to exclude:

arr = np.array([1, 2, 3, 4, 5]) exclude = np.array([2, 4]) new_arr = np.setdiff1d(arr, exclude) print(new_arr) # [1, 3, 5]

Shields up: strategic use of boolean masks

Boolean masks, like knights in shining armor, protect your array from unwanted elements. Here's how to command your knights using np.arange and np.isin:

arr = np.array([1, 2, 3, 4, 5]) mask = np.isin(np.arange(arr.size), [1, 3]) new_arr = arr[~mask] print(new_arr) # [1, 3, 5]

Masterclass in advanced removal techniques

Combining conditions: Powers unite!

Numpy gives you the superpower to combine conditions using logical operations. Create power-packed masks like:

arr = np.array([1, 2, 3, 4, 5, 6, 7, 8, 9]) # Kick out even numbers and numbers greater than 7 (I mean, they had it coming right?) new_arr = arr[~((arr % 2 == 0) | (arr > 7))] print(new_arr) # [1, 3, 5, 7]

Using np.where for sneak attacks

Suppose you want to remove elements based on a condition, like a predator stalking its prey. np.where() is your perfect ally:

arr = np.array([1, 2, 3, 4, 5]) # Get indices of elements cowering below 4 indices = np.where(arr < 4) # Use np.delete() to remove these elements. It's almost like magic! new_arr = np.delete(arr, indices) print(new_arr) # [4, 5]

Multi-directional assault on multidimensional arrays

For dealing with multidimensional arrays, consider axis parameters like a strategic genius:

arr = np.array([[1, 2], [3, 4], [5, 6]]) # Unseat the first and third row royals new_arr = np.delete(arr, [0, 2], axis=0) print(new_arr) # [[3, 4]]