How to read a file line-by-line into a list?
To read a file line-by-line into a list in Python, you can use a list comprehension with the open()
function. This approach simultaneously removes trailing whitespaces from each line:
This efficiently condenses opening the file, stripping spaces and line breaks, and constructing our list into one line of code.
Applying best practices for file I/O
When it comes to file input/output (I/O), it's critical to stick to best practices.
Auto-closing files using Context Managers
Always ensure your files are properly closed after use. A context manager (with
) makes sure your files are closed automatically:
Navigating through Large Files
Loading large files can consume much of your memory. Instead, iterate through the file line by line, reducing memory usage:
Python 3.8's Walrus Operator
Why not use the walrus operator (:=
)? This operator allows you to assign and evaluate an expression in one step, for a cleaner and more readable code:
Handling different file formats
Different files can require different handling:
- Text files: We use
mode='r'
to tell Python we're dealing with a text file. - Binary files: For files containing non-text data (like images), use
mode='rb'
to read the file in binary mode.
Respecting file encodings
It's essential to set the character encoding explicitly to 'UTF-8' to prevent misinterpretation of non-ASCII characters:
Advanced tips and common pitfalls
Master file paths
To ensure the file path is correct and platform-independent, use the pathlib
module:
Handle newline characters
Be aware of newline characters ('\n'
) at the end of each line. The strip()
method conveniently removes them.
Apply Lazy evaluation for memory efficiency
To lv up^^ go for a generator function which yields lines one by one, treating memory gently especially relevant for large files.
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