How to get 0-padded binary representation of an integer in java?
If you are in a hurry and want to instantly create a 32-bit padded binary string, brace yourself - because String.format()
is the champion of the ring:
Just remember to replace 32
with your desired number of characters (not fingers), alright?
The "why" and "when" of other methods
Although String.format()
might be great when you need fixed numbers of characters, alternate methods have their own value.
If you are working with negative numbers, let the mambo of |
and <<
do the magic:
But here's a secret from the web developers’ corner: when efficient padding is your top priority, immediately call StringUtils.leftPad()
from Apache Commons Lang:
Too posh to push? Roll up your sleeves and customize your own padding using custom loops or Arrays.fill()
. Result? The same, but now with 100% more feeling of superiority and 0 external dependencies:
And remember - always check the string length before padding. Otherwise, your binary string might end up longer than a boring monologue.
Getting your hands dirty with bitwise manipulation
Bitwise operations might sound scarier than a horror movie, but they are your secret weapon to perform incredible tasks.
Working with negative integers? Ensure the very correct sign by smoothly sliding (1 << len) | (val & ((1 << len) - 1))
into your code routine.
The masking operation (val & ((1 << len) - 1))
is more than a masquerade – it is a mask that lets only len
bits pass through it, clipping the integer to the permitted length.
The dynamic lengths are no more a mystery. To stay adaptive, just shift 1
left by len
bits. It will create a binary string of ones, and hence, make you the master of padding techniques.
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