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How to ensure order of processing in java8 streams?

java
stream-engineering
best-practices
performance
Anton ShumikhinbyAnton Shumikhin·Nov 14, 2024
TLDR

Ensure processing order in Java 8 streams by using a sequential stream from an ordered collection like List with stream(). Be cautious about parallel streams as concurrent processing can disrupt the order. Here's the crux:

List<String> orderedList = Arrays.asList("1", "2", "3"); orderedList.stream() .forEach(System.out::println); // Prints 1, 2, 3 in order - no sorcery here!

This sequential stream respects the natural order of the collection source, making it a go-to for order-sensitive operations.

Ensuring order: The code explanations

Honoring order: forEachOrdered

If order is your priority over performance, opt for forEachOrdered() over forEach:

Stream<String> lineStream = Files.lines(Paths.get("file.txt")); lineStream.forEachOrdered(System.out::println); // Reads a bedtime story to your lines, in order!

Transform and behold!

Stream transformations using functions like map retain the order in a sequential stream:

orderedList.stream() .map(s -> "Number " + s) .forEachOrdered(System.out::println); // Announces your numbers like it's a lottery draw

Skip and limit

Order preservation stays intact while limiting or skipping elements:

orderedList.stream() .skip(1) .limit(2) .forEach(System.out::println); // Removes 1, keeps 2 and 3 like a favorite child

Watch your step with sorted

While sorted ensures order, be aware it could change the original order to match the sorting condition.

Time-saving with unordered streams

When order isn't essential, unordered() can be a performance booster for parallel processing:

unorderedList.parallelStream() .unordered() .forEach(System.out::println); // Unleashes elements like wild horses, with no particular order!

This tactic allows the JVM to provide a faster processing ride.

Key takeaways on Stream Operations

Generating order: Stream.iterate

Utilize Stream.iterate for creating ordered streams:

Stream.iterate(0, n -> n + 1) .limit(10) .forEach(System.out::println); // Meet the orderly family of numbers 0-9!

On the contrary, Stream.generate offers no order guarantees:

Stream.generate(Math::random) .limit(5) .forEach(System.out::println); // Roulette time! No order guaranteed

Unveiling parallel streams

Parallel streams promise ample performance gains but remember, they assure the end list's order, not the order of operation execution:

List<Integer> numbers = IntStream.rangeClosed(1, 1000) .boxed() .collect(Collectors.toList()); numbers.parallelStream() .mapToInt(i -> heavyComputation(i)) .boxed() .collect(Collectors.toList()); // It's like having all ducks in a row, just not sure who quacked first!

The terminal operation like collect ensures the sequence is re-established.

Wise Practices

  • Check and respect the documentation for each stream function about its order preservation.
  • If order isn't a priority, use unordered() combined with parallel processing for a performance upgrade.
  • Rest assured as IntStream.range or Files.lines inherently churn out ordered streams.
  • Know that typically, stream pipelines can achieve satisfying parallelization while still saving the order.