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How to check if a string contains an element from a list in Python

python
list-comprehensions
string-manipulation
boolean-expressions
Alex KataevbyAlex Kataev·Oct 11, 2024
TLDR

Scrutinize whether a string enlists any list item subtly with the below line of magic:

any(item in my_string for item in my_list)

True if a match exists, otherwise False. The operation halts on the first match. However, remember that the contextual location might be pivotal for scenarios like URLs or filenames.

Digging into specific solutions

String manipulation for results: Right at the start or the very end?

At times, it's imperative to ensure if the match is rooted at the beginning or the tail end of the string. Python’s exclusive startswith() and endswith() functions can perform this check. Notably, these divas love working with tuples; hence you can check multiple starters or endings seamlessly:

my_string.endswith(tuple(my_list)) # Trailing with a list item? Yes or No! my_string.startswith(tuple(my_list)) # Leading with a list item? Choose wisely!

Handling URLs and file paths like a pro

When juggling with URLs, leverage the urlparse library to accurately identify where you expect the match. For file paths, get help from your buddy os.path.splitext to separate the file extension for a reliable comparison:

from urllib.parse import urlparse from os.path import splitext parsed_url = urlparse(my_string) file_name, file_extension = splitext(parsed_url.path) if file_extension in my_list: # Verify against a list of extensions. It's more fun than it sounds! print("Your wish came true - a valid extension found!")

Fearing false positives? Worry not!

In the realm of security-intensive operations, you can’t afford false positives. Get down to the details with rigorous matching rules or regular expressions for pristine precision.

import re # Pattern: Matches whole words only. # With great power comes - never mind, just remember to use it carefully! pattern = r'\b(?:' + '|'.join(re.escape(word) for word in my_list) + r')\b' if re.search(pattern, my_string): print("Jackpot! Exact word match found.")

Power at your fingertips: List Comprehensions

Here is where list comprehensions show their muscle, transforming list processing into a clean, smooth boolean expression:

# Check presence of matches and also capture matches = [item for item in my_list if item in my_string] has_matches = bool(matches)

Above, matches holds a trophy of all found items and has_matches is the indicator flag's status regarding a match.