How to check if a string array contains one string in JavaScript?
The includes()
method is your quick and easy solution to identify if a string is in an array:
It will return true if 'banana' is partying with the fruits
, otherwise false - the party's a bore without 'banana'.
Digging Deeper: Case sensitivity and indexOf
Hang on to your hats, because the includes()
method is case-sensitive. It differentiates between 'Banana' and 'banana', essentially having a it's-not-you-it's-me moment. You can circumvent this by ensuring all strings are in the same case:
includes()
is not invited to the IE 8 and lower party. In this case, use the indexOf()
method which finds the index of the found element, or -1 if it's MIA:
For inviting includes()
to old parties, MDN has a polyfill - essentially a golden ticket.
Extending the Party Invite: Array Prototypes
Making the Array
prototype extend the contains
method might feel like a shortcut:
However, but it's like adding a new rule to Cards Against Humanity mid-game - quirky, unpredictable, and causing unexpected behaviors.
Navigating Trickier Waters: Edge Cases and Alternatives
You don’t want an empty array to crash the party:
Also, be on the lookout when the search string is empty:
Consider some()
, the clever cousin of includes()
, for complex checks:
Common Pitfalls & Safe Practices
Manually checking each guest via a loop could work in a pinch but invokes the formal tedium of a Victorian dance:
Lean on built-in methods for efficiency and readability:
Ensure to validate inputs. Do not presume the nature of the arguments passed:
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