How do I initialize a byte array in Java?
First things first, creating an empty byte array with a fixed size and default zero values:
Next, creating a byte array that comes with predefined content:
To initialize byte array from a hexadecimal string, Java 17 users are in luck with java.util.HexFormat
:
Not on Java 17? No worries, a custom hexStringToByteArray
function can come to the rescue:
For processing UUIDs or larger hex inputs, advanced solutions like Google Guava's BaseEncoding
or parsing methods from the UUID
class are worth considering.
Utility Zoom-in
Utility classes paint a rainbow in our code by simplifying it, and making it more readable and maintainable. Methods like getBytes()
or DatatypeConverter.parseHexBinary
do the magic of transforming arrays from strings and hex strings, respectively. By embracing a dash of performance overhead, we can unlock the beauty of clearer, more maintainable code.
Conversion: From Characters to Bytes
Conversion between different representations is a common practice in programming. At times, you may need to transform a char
array or a large hex input into a byte array. Here's how:
Character array to byte array
Working with large hex inputs
For sizeable or complex hex strings, Google Guava's BaseEncoding handles the jungle of case sensitivity and hex conversion:
Crafting byte arrays from UUIDs
Need a byte array that represents a UUID? The UUID
class offers a clean solution:
Through these conversions, you can ensure to obtain the correct byte array representation.
Tripping over stones: Common pitfalls and performance considerations
Programming is not always a straight line. Be aware of obstacles like character encoding issues when using getBytes()
. While utilizing utility functions come with a performance cost, they offer greater benefits in clarity and maintainability. Remember, performance is a functional requirement; only optimize when necessary.
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