How do I convert a Java 8 IntStream to a List?
To swiftly convert a Java 8 IntStream
to a List<Integer>
, use boxed()
followed by collect(Collectors.toList())
:
The boxed()
method wraps primitive int
values into Integer
objects and collect(Collectors.toList())
converts these into the final List<Integer>
.
Upgrade for Java 16 users
In Java 16, reduce your typed characters and acrobatics with the smoother toList
method :
This nifty method provides an unmodifiable List
, scaling up your performance game.
Eclipse Collections: The Ferrari of conversions
Consider high performance Eclipse Collections when you need to live life in the fast lane:
Why? It shuns the annoying boxing overhead. Bye unnecessary baggage!
Manual driving: custom collectors
If you like to drive manual or just staying classy with functional programming, create a List<Integer>
using custom collector functions:
Comment: Because some of us like it old school.
When immutability is a religion
To enforce immutability post Java 8 and pre Java 16:
This shields your List
from meddlesome mods, throwing UnsupportedOperationException
if any dares.
Before vs. After
Stream to List: Faster than your food delivery!
Dealing with int array refugees
If you have an int
array begging for conversion, Arrays.stream
is your hero:
Comment: Who said arrays can't be elegant?
For the data behemoths
Handling large datasets? Choose your collection based on usage. Index-based access? Definitely List
. Else, consider Set
/Map
based on data uniqueness and access needs.
Watch your step: Potential pitfalls
That boxing glove can punch
The ergonomic boxing does levy a cost on performance. For large collections or high-use scenarios, think about the overhead.
Immortality has a price
Immutable lists sound cool until you try to modify them. Sudden UnsupportedOperationException
can ruin your coffee break.
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