How can I find and update values in an array of objects?
To update values within an array of objects, use .map()
for creating a new array with updated elements. See this:
This function will change name
from 'Bob'
to 'Robert'
without affecting other properties.
The direct approach: findIndex
You can also change values directly in the original array using .findIndex()
:
Note: This modifies the original users
array, use it only if such mutations are acceptable.
Dealing with clones: forEach
If you suspect there might be twins in your array (duplicate names), use .forEach()
to ensure all matching objects are updated:
Watch out for fake IDs
Unique identifiers are paramount for consistent results. If not unique, you risk doing a cosmetic surgery on the wrong patient!
Gentle touch with Object.assign
Use Object.assign
to ensure you don't accidentally mutate original references, it merges properties of two objects:
Don't break reactivity: Reassigning updated arrays
When working with reactive frameworks, make sure you reassign the updated array to the original variable:
Going turbo: dictionaries for performance
Dictionary objects offer key-based access to items, which is faster than iteration methods for large arrays:
Level up with spread syntax
In modern JavaScript, use spread syntax to make safe updates by creating new objects:
Third-party helper: lodash
When native methods aren't enough, lodash offers useful functions for complex operations:
Playing nice with reactive frameworks
In reactive frameworks like Vue, Angular, or React, it's essential to handle state updates properly:
Vue example:
Maintaining readability and healthy codebase
For larger projects, consider creating utility functions for object manipulation and store them in dedicated modules. It promotes readability and makes your code DRY (don't repeat yourself).
Playing nice with functional programming
Finally, if you live in the functional programming world, prefer immutable updates over direct mutations. It prevents nasty side effects and makes your code safer and more predictable.
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