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Common elements comparison between 2 lists

python
list-comparison
python-optimization
data-structures
Nikita BarsukovbyNikita Barsukov·Dec 2, 2024
TLDR

Let's swiftly find common elements between two lists via set intersection in Python:

list1 = [1, 2, 3, 4, 5] list2 = [3, 4, 5, 6, 7] common_elements = list(set(list1) & set(list2)) # Behold! Returns [3, 4, 5] print(common_elements)

Diverse scenarios and solutions

Peeking under the hood, Python offers a range of strategies for diverse scenarios, from preserving order or finding intersections for immutable lists to optimizing operations for numerical data.

Set in stone: Immutable list intersections

# When your data is as unchangeable as your partner's movie preferences immutable_common_elements = list(frozenset(list1).intersection(list2)) print(immutable_common_elements) # Fulfills its duty without altering the lists

Numbers only: Numerical efficiency with NumPy

import numpy as np numeric_list1 = np.array(list1) numeric_list2 = np.array(list2) # Like a superhero for numerical lists! common_numbers = np.intersect1d(numeric_list1, numeric_list2) print(common_numbers) # NP (No Problem) for NumPy!

Practical cornerstones and pro-tips

Dive deeper with practical considerations: tackling duplicates, type-specific comparisons, large lists, and much more to become a list-slaying Pythonista.

Dealing with duplicates

from collections import Counter counter1 = Counter(list1) counter2 = Counter(list2) # Keeps the peace among duplicates! common_elements = list((counter1 & counter2).elements()) print(common_elements) # Huzzah! Handles duplicates

Set-free solution

common_elements_no_set = [e for e in list1 if e in list2] # Who needs sets when you got skills! print(common_elements_no_set)

Type filter: Mixed type comparison:

common_elements_str = [str(element) for element in list1 if element in list2 and isinstance(element, str)] # Separates humans from robots, string from ints. print(common_elements_str)

Work smart, not hard: Performance considerations

Python's methods like set intersection are generally more efficient than list comprehensions when working with large lists, primarily due to hash table implementations in Python sets.